['00', '11"', 'aa', 'bb', "cc'"]
This is in Python. I want to strip off the double quotes so that my output becomes
['00', '11', 'aa', 'bb', 'cc']
How do I do this?
Looks like you've to use the str.strip()
function two times here. First to remove the "
and then '
.
In [1]: lis=['00', '11"', 'aa', 'bb', "cc'"]
In [2]: [x.strip('"').strip("'") for x in lis]
Out[2]: ['00', '11', 'aa', 'bb', 'cc']
or as suggested by @DSM we don't require 2 strip()
calls:
In [14]: [x.strip("'" '"') for x in lis]
Out[14]: ['00', '11', 'aa', 'bb', 'cc']
because, neighboring string literal are automatically combined :
In [15]: "'" '"'
Out[15]: '\'"'
In [16]: "a"'b'"c"'d'
Out[16]: 'abcd'
Another alternative can be regex
:
In [6]: [re.search(r'\w+',x).group() for x in lis]
Out[6]: ['00', '11', 'aa', 'bb', 'cc']
Python 2.6 and newer Python 2.x versions:
line = ['00', '11"', 'aa', 'bb', "cc'"]
line = [x.translate(None,'\'\"') for x in line]
You should make use of regular expressions. Have a look at this site for more information.
http://www.regular-expressions.info/python.html
Regular expressions are the code version of Find and Replace. What you are looking for is to use a regular expression such as r'[\\'\\"]' and replace it with an empty string. While Python is not my biggest strength, that should give you a push in the right direction.
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