TypeError: start() 接受 1 个位置参数，但给出了 2 个

Question

以下程序应该在按住“Ctrl”键时自动单击并在松开键时停止并完全停止是 tkinter window 关闭。 到目前为止，一切都很好。

import keyboard
import pyautogui 
import threading 
from tkinter import *
from tkinter import ttk


def convert_to_pause2(clicks_per_second2):
    clicks_per_second2 = min(clicks_per_second2, 20)
    return 1 / clicks_per_second2

def repeat_function2(kill_event2, int2):
    while not kill_event2.is_set():
        pyautogui.PAUSE = convert_to_pause2(int2.get())
        pyautogui.click()
        
        
def hotkey_thread_loop2(int2):
    
    while True:
        kill_event2 = threading.Event()
        
        new_thread2 = threading.Thread(target=lambda: repeat_function2(kill_event2, int2))
        keyboard.on_press_key('ctrl',new_thread2.start)
        keyboard.on_release_key('ctrl',kill_event2.set())
        keyboard.wait('ctrl', keyboard.KEY_UP)
        keyboard.unhook_all()

# Start the main program
if __name__ == "__main__":
    
    root = Tk()
    root.geometry('500x400')
  
    bovar2 = IntVar()
   
    scale2 = Scale(root,orient=HORIZONTAL, from_=0,to=20,variable=bovar2)
    scale2.pack(side=RIGHT)
    
    
    
   
    
    hotkey_thread2 = threading.Thread(target=lambda: hotkey_thread_loop2(bovar2),
                                     daemon=True)
    
    hotkey_thread2.start()
    
    
   
    root.mainloop()

当我按住 ctrl 键启动程序时，它会显示以下错误：

Exception in thread Thread-8:
Traceback (most recent call last):
  File "/usr/lib/python3.8/threading.py", line 932, in _bootstrap_inner
    self.run()
  File "/usr/lib/python3.8/threading.py", line 870, in run
    self._target(*self._args, **self._kwargs)
  File "/usr/local/lib/python3.8/dist-packages/keyboard/_generic.py", line 58, in process
    if self.pre_process_event(event):
  File "/usr/local/lib/python3.8/dist-packages/keyboard/__init__.py", line 213, in pre_process_event
    key_hook(event)
  File "/usr/local/lib/python3.8/dist-packages/keyboard/__init__.py", line 510, in <lambda>
    return hook_key(key, lambda e: e.event_type == KEY_UP or callback(e), suppress=suppress)
TypeError: start() takes 1 positional argument but 2 were given

但是我对鼠标模块做了同样的事情，没有问题，所以我知道出了什么问题

Answer 1

我这样做了： lambda *a:new_thread2.start()并且它消除了错误，但是现在您遇到了一个新问题，您不能多次启动线程，并且您的循环将启动它远不止于此。

有什么原因导致这不正是您想要做的吗？ 似乎您的所有线程都只是在尝试侦听并等待按键。 Tkinter 已经这样做了，而且它比您当前的方法更简洁。

import pyautogui, tkinter as tk

class App(tk.Tk):
    def __init__(self):
        tk.Tk.__init__(self)
        self.geometry('500x400')
        
        self.bovar = tk.IntVar()
        
        self.bind('<Control_L>', self._handler)
        #self.bind('<Control_R>', self._handler) #if you want both Control keys
        
        #you can't start scale at 0 if you intend for it to be a divisor
        scale = tk.Scale(self, orient=tk.HORIZONTAL, from_=1, to=20, variable=self.bovar)
        scale.pack(side=tk.RIGHT)
        
    def _handler(self, event):
        #the scale only goes to 20 so your min was not necessary
        pyautogui.PAUSE = 1/self.bovar.get()
        pyautogui.click()


if __name__ == "__main__":
    App().mainloop()