i'm new to opencv & it's developing. I have x,y,z coordinates ( 0.00949334694383068, -0.3999829847985352, 0.8449078780010854) by using the given coordinates how could i find the direction.
for an example
input one : x,y,z = 0.00949334694383068, -0.3999829847985352, 0.8449078780010854
input two : x,y,z = 0.01603883281370779, 0.6066595296580494, 0.5342810849038371
At the finally i want to compare input_one direction and input_two direction. Any help is appreciated
What you're trying to do is called calculating the azimuth. If you're interested in doing this for navigational or geographic purposes and need a thorough understanding of this, you can start here:
Otherwise you could look for a library for calculating the azimuth bases on 3d co-ordinates
This is called vector math.
"Coordinates" are a special kind of vector, relative to some origin (in your case x=0,y=0,z=0
). For that reason, the difference x1-x2, y1-y2, z1-z2
is a vector from point 2 to point 1. The inverse x2-x1, y2-y1, z2-z1
is a vector from point 1 to point 2.
The direction of a vector is usually defined by ignoring its length, or alternatively by setting its length to one. So we need to first define the length, which is L = √(x*x + y*y + z*z)
. We can define the vector x/L, y/L, z/L
which points in the same direction as x,y,z
but with length one.
Finally, to compare two directions we can calculate the inner product of those two directions: x1/L1 * x2/L2 + y1/L1 * y2/L2 + z1/L1 * z2/L2
. If that's one, they point in the same direction. If it's 0, they're orthogonal. If it's -1, they point in opposite directions.
As you can see, the vector 0,0,0 has length 0 and no direction. That can complicate things a bit.
In OpenCV: class Vec . The length function is called norm(v)
and the inner product is called v1.mul(v2)
The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.